Q:

Difficulty finding the sum of a hyperbolic function.

Can someone please point out where I am (If I am) going wrong during the solution process of the following question:
I have been presented with the following :
$$4sinh(2ln(2))-cosh(ln2)$$
and told by my tutor the solution is 10. however I cannot obtain this value, the steps I take are as follows :
$$(4*(e^{ln(2)^2} - e^{-ln(2)^2}/2)) - (e^{ln(2)} + e^{-ln(2)}/2) $$
$$2e^{2ln(2)} - 2e^{-2ln(2)} - 0.5e^{ln(2)} + 0.5e^{-ln(2)} $$
$$8 - 0.5 - 1 + 0.25$$
$$6.75$$
For added clarity I will show a picture of notes I have regarding the question :

I would very much appreciate if someone can help me reach a solution as to why my answer differs from the tutors. Thank you.

A:

The answer should be $6.25$.
\begin{align}
 & 4 \sinh (2 \ln 2) - \cosh(\ln2 ) \\
=& 2 \left(e^{2\ln2}-e^{-2\ln2} \right) - \frac{e^{\ln2}+e^{-\ln2}}{2}\\
=& 2(4-0.25)-\frac{2+0.5}{2}\\
=& 7.5-1.25 = 6.25.
\end{align}

