Q:

Groovy XmlSlurper get value of the node without children

I'm parsing HTML and trying to value of a parent node itself, without values of the children nodes.
HTML example:
<html>
    <body>
        <div>
             <a href="http://intro.com">extra stuff</a>
             Text I would like to get.
             <a href="http://example.com">link to example</a>
        </div>
    </body>
</html>

Code:
def tagsoupParser = new org.ccil.cowan.tagsoup.Parser()
def slurper = new XmlSlurper(tagsoupParser)
def htmlParsed = slurper.parseText(stringToParse)

println htmlParsed.body.div[0]

However above code returns:

extra stuff Text I would like to get. link to example

How can I get only parent node value without children? Example:

Text I would like to get.

P.S:
I tried removing extra elements by doing substring but it proves to be unreliable.

A:

If you switch to using XmlParser instead of XmlSlurper, you can do:
println htmlParsed.body.div[0].localText()[0]

Assuming you are on Groovy 2.3+

