Q:

Bash Script - Copy latest version of a file in a directory recursively

Below, I am trying to find the latest version of a file that could be in multiple directories.  
Example Directory:
~inventory/emails/2012/06/InventoryFeed-Activev2.csv    2012/06/05
~inventory/emails/2012/06/InventoryFeed-Activev1.csv    2012/06/03
~inventory/emails/2012/06/InventoryFeed-Activev.csv     2012/06/01

Heres the bash script:
#!/bin/bash

FILE = $(find ~/inventory/emails/ -name INVENTORYFEED-Active\*.csv | sort -n | tail -1)
#echo $FILE #For Testing

cp $FILE ~/inventory/Feed-active.csv;

The error I am getting is: 
./inventory.sh: line 5: FILE: command not found

The script should copy the newest file as attempted above.
Two questions:  
First, is this the best method to achive what I want?
Secondly, Whats wrong above? 

A:

It looks good, but you have spaces around the = sign. This won't work. Try:
#!/bin/bash

FILE=$(find ~/inventory/emails/ -name INVENTORYFEED-Active\*.csv | sort -n | tail -1)
#echo $FILE #For Testing

cp $FILE ~/inventory/Feed-active.csv;

