Q:

Maclaurin series expansion of $f(x) = \ln(3x^2 +4x +1)$

Can someone please explain how I do the following Maclaurin series?
$$f(x) = \ln(3x^2 +4x +1)$$

A:

Hint: $$\ln(3x^2 + 4x + 1) = \ln(3x+1) + \ln(x+1)$$

