Q:

How to sort json data in groovy in alphabetic order?

I want to sort an json data which is like this 
def json = []
for ( int i=10;i>1;i--){

    if (i==10 || i==9 ){
         json << [ name:"xyz",
            id:i
        ]
    }else 
    if (i==8 || i==7 ){
          json << [ name:"abc",
             id:i
            ]
    }

}
// def jsondata = [success:true, rows:json]

def jsondata = [success:true, rows:json.sort(false) { it.name }]

print jsondata​
groovy.lang.MissingMethodException: No signature of method: java.util.ArrayList.sort() is applicable for argument types: (java.lang.Boolean, com.cs.AdminController$_closure15_closure83) values: [false, com.cs.controllers.AdminController$_closure15_closure83@3e020351]
Possible solutions: sort(), sort(java.util.Comparator), sort(groovy.lang.Closure), wait(), size(), size()

I want that data to be sorted alphabetic order ascending or descending 
above one is working in a groovy console but not in my program , do i need to add something else like lib ? 

A:

Your output format seems to have no similarity to your code you posted
Also, your code you posted cannot just be run by someone trying to answer this question.
So this will be an educated guess...
Try:
def jsondata = [success:true, rows:json.sort(false) { it.name }, total:totalCount]

If you're using groovy from way back in the day for some unknown reason, then just drop the false, but beware as this will mutate your json list...
def jsondata = [success:true, rows:json.sort { it.name }, total:totalCount]

