Q:

Split number into two parts

I'm trying to split number (8bit) (0..255) into two numbers like this:
100 (binary 01100100) into 6(0110) and 4(0100).
In C I do it in such way:
short row = value >> 4; //value - uint8_t
short col = (row << 4) ^ value;

In Java I do it the other way (because C like code don't work properly):
short v1 = (byte)(value >> 4);
short v2 = (byte)((byte)(value << 4) >>> 4);

It works for numbers from 0 to 103. But for numbers greater than 103 it doesn't work.
p.s.
Actually problem is here:
short v2 = (byte)((byte)(value) >>> 4);
=>104 (1101000). I expected to see something like this: 00001000, but result is 11111000 
=>103 (1100111). Result is 111;

Fix.
I fixed it in such way:
short value = (byte)255;
short v1 = 0;
short v2 = 0;

for(int i = 3; i >= 0; i--) {
    v2 = (short) (v2 << 1 | ((value >> i) & 1));
    v1 = (short) (v1 << 1 | (value >> (i + 4) & 1));
}
System.out.println(v1 + " " + v2);

But I prefer the C way, it's more simple.

A:

short row = (value >> 4) & 0x0F;
short col = value & 0x0F;

This should also work in C.
& keeps only the bits which are 1 at the same position:
11111000   // 104
00001111   // 0x0F == 15
--------
00001000   // 104 & 0x0F == 8
           // because only the fourth bit from right is 1 in both numbers!

