Q:

Multiplying scientific notation and modifying the precision in awk

I have csv files and I need to scale the first column of csv file with value 1.3. I am able to scale the first column of csv file with value 1.3 using awk. Here is the one line code which I  have used for scaling:
$ awk -F, '{$1=$1*1.3;print}' OFS=, input.csv > output.csv

Now the problem is that after scaling, I want the result upto 9 or 10 decimal places but I am getting upto 5 decimal places.
input.csv file format:
9.876160000E-07 , 6.5940E-03
9.876180000E-07 , 4.0718E-03

output.csv file format (after running awk command):
1.2839e-06,      6.5940E-03
1.2839e-06,      4.0718E-03

Expected Output.csv file format:
1.28390080e-06,  6.5940E-03
1.28390340e-06,  4.0718E-03

What to change in awk command to get the expected result?

A:

Like this, using sprintf:
$ awk '{$1=sprintf("%.8e",$1*1.3);print}' file
1.28390080e-06 , 6.5940E-03
1.28390340e-06 , 4.0718E-03

