Q:

Counting all the hearts

The Arthur family ( Henrik, Olga, Heather and Kristophe) are playing Bridge at the dining table with a standard deck of cards.

Taking into account every possibility
How many hearts are at that table?

A:

First,

there are $4$ human hearts.

Then,

Considering this image of standard playing cards:
 
The cards have $2$ hearts on each card next to the name of the card, each face card has $2$ additional hearts in the art, and every other card has its number of hearts, totaling $$2\cdot13+3\cdot2+(1+2+\dots+10)=26+6+55=87.$$

Finally,

The family's names contain letters that form the word heart. We will use Dr Xorile's suggestion to count the total number of ways to form heart using different instances of the letters in their names. If we take their full names: Henrik Arthur, Olga Arthur, Heather Arthur, and Kristophe Arthur, we count $8$ H's, $4$ E's, $6$ A's, $11$ R's, and $6$ T's, giving $$8\cdot4\cdot6\cdot11\cdot6=12672.$$

which adds up to

$4+87+12672=12763$.

A:

Starting with noedne's analysis of 

87 hearts 

from the card deck alone. We also have:

four (I assume) humans, that have one heart each... except that the two women could be pregnant (take into account every possibility!), and with humans twinning is reasonable, but triplets are pretty rare, so I would say up to 8 human hearts.

Oops, almost forgot to look at:

 The text itself! The Arthur family has a cleverly hidden heart, and there are enough letters in the other names for 2 more, adding these to the human and card hearts are 87+8+3 for a grand total of 98 hearts. I think this is a stretch, but the fact that there are 52 cards in a deck also looks like a heart(), so that would make 99.

Or if you want to be absolutely ridiculous:

 Octuplets have been born a few times, so you could have 4+8+8=20 human hearts for a grand total of 110, but at that rate do you count multiple births higher than eight as long as they can have a beating heart in the womb? That's why I consider this a ridiculous option.

