Q:

Using Scala 2.10 `to` to convert a List to a SortedMap

I am trying to convert a scala.collection.immutable.List of pairs to a scala.collection.immutable.SortedMap using the new to method from Scala 2.10, but I get a compile-time error:
scala> List((1, "Fred"), (2, "Barney")).to[scala.collection.immutable.SortedMap]
<console>:10: error: scala.collection.immutable.SortedMap takes two type parameters, expected: one
              List((1, "Fred"), (2, "Barney")).to[SortedMap]
                                                  ^

Can this be done using the to method? Am I missing an intermediate method call?

A:

I had a similar question some time ago and came up with this: 
SortedMap( list: _*)

So you can do it like :
val map =  SortedMap( List((1, "Fred"), (2, "Barney")): _*)

The _* means you take the Seqs elements instead of the Seq itself as parameter. 

A:

@gourlaysama already explained why it does not compile, and @Chirlo provided the simplest (and recommended) work around: SortedMap( list: _*).
I'd like to propose an alternative:
import collection.Traversable
import collection.generic.CanBuildFrom
implicit class RichPairTraversable[A,B]( t: Traversable[(A,B)] ) {
  def toPairCol[Col[A,B]](implicit cbf: CanBuildFrom[Nothing, (A,B), Col[A, B]]): Col[A, B] = {
    val b = cbf()
    b.sizeHint(t)
    b ++= t
    b.result
  }  
}

Some test in the REPL:
scala> List((1, "Fred"), (2, "Barney")).toPairCol[scala.collection.immutable.SortedMap]
res0: scala.collection.immutable.SortedMap[Int,String] = Map(1 -> Fred, 2 -> Barney)

scala> List((1, "Fred"), (2, "Barney")).toPairCol[scala.collection.immutable.HashMap]
res1: scala.collection.immutable.HashMap[Int,String] = Map(1 -> Fred, 2 -> Barney)

Now, I will probably not use it in production, given that doing SortedMap( list: _* ) is not that
hard and requires no magic.

